Question

The Sibley High-Energy Particle Accelerator has a maximum average proton current of 1.0 mA at energy of 800 MeV.
a. How many protons strike the target per unit time?
b. What is the current density of the beam if its cross-sectional radius is 2.5cm?
c. The beam is projected in pulses. There are 120 pulses/s, and between each pulse there is a break, such that the beam is on 8% of the time. What is the length of each pulse and what is the length of the length of time between the pulses?
d. What is the average beam current during each pulse?
e. How many protons strike the target per pulse?

Answer 1

Can somebody help me out by explaining this and checking my answers..

a. I divided current by charge of an electron. I got 6.24*10^15 protons strike the target per second.

b. I divided current by PI * (radius given)^2. I got J = .509

c. 1 pulse = .008333 seconds (1/120)
but since the beam is only up for 8% of the time.
1 pulse = .008333*(.08) seconds = x
time between pulses = .008333 - x

d & e I don't understand yet.