Question

3x^2-12x=-7

Answer 1

use \[x= \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] where a = 3 b=-12 and c= 7

Answer 2

clear?

Answer 3

Yes thank you :)

Answer 4

:)

Answer 5

Actually the book says that the answer is 2 plus or minus the squareroot of 15 over 3. i got 4 square root 15 as my answer.

Answer 6

wait

Answer 7

\[x= \frac{ -(-12) \pm \sqrt {(-12)^2-4*3*-7} }{ 2*3 }=\frac{ 12 \pm \sqrt {144+84} }{ 6 }=\frac{ 12 \pm \sqrt{228 } }{ 6 }\]

Answer 8

simplification of this should be your answer

Answer 9

sorry there is a mistake its just 7 not -7

Answer 10

\[x=\frac{ 12 \pm \sqrt{60} }{ 6 }= \frac{ 12 \pm 2 \sqrt{15} }{ 6 }=\frac{ 6 \pm \sqrt{15} }{ 3 }\] :)

Answer 11

THANK YOU SO SO MUCH! I finally understand the concept :)