Question

sinx/(sinx+cosx)=tanx/(1+tanx)

Answer 1

\[\frac{ sinx}{ sinx+cosx} = \frac{ tanx }{ 1+tanx }\]

Answer 2

\[\frac{ sinx + \cos x }{\sin x } = \frac{1 + tanx}{tanx}\] take the inverse of each side

Answer 3

hint: \[1+ \tan x = \frac{ \sin x + \cos x }{\cos x} \]
as \[\tan x = \frac{ \sin x }{ \cos x }\]
try it yourself/