Question

According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have?

Answer 1

According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have?

A. Four

B. Three

C. Three or one

D. Two or zero
**im not too sure but i think the answer is D. two or zero. am i right??

Answer 2

The number of possible negative real roots is equal or less than the total number of sign changes. How many sign changes do you see?

Answer 3

2.. i think the answer is D. two or zero... is that correct??

Answer 4

Yes, I agree with D.

Answer 5

thanks! :)

Answer 6

thanks! :)

Answer 7

You're welcome!