Question

H9P1: RESPONSE TO A DELAYED IMPULSE

Note: In this problem we have chosen numbers for the part parameters to make it easier to compute an answer :-). By the way, it is also hard to arrange zero resistance, except with superconducting materials at very low temperatures.
In the circuit shown below L=65.0H and C=6.24mF.

The current source puts out an impulse of area A=2/π=0.64 Coulombs at time t=1.0s.

At t=0 the state is: vC(0)=0.0 and iL(0)=1.0.

The equation governing the evolution of the inductor current in this circuit is

d2iL(t)dt2+1LCiL(t)=ALCδ(t−1.0)
Can any one help me

Answer 1

callisto...can u help me

Answer 2

vision 89 can u help me

Answer 3

reply

Answer 4

are u active vision89

Answer 5

please.......someone help

Answer 6

a)0.25
b)?
c)?
d)0
e)?
f)0
g)0
h)0

Answer 7

0.250122093132
32.5
32.5
0
-102.05
0
0
0

Answer 8

In my case:

H9P1
a - 0.25
b - 85
c - 85
d - 0
e - -267.03
f - 0
g - 0
h - 0

Answer 9

thankyou Abhay.....u are helping the best possible ways u can.......u helped me aerlier in multivibrators

Answer 10

my pleasure bro :)

Answer 11

but in case they are giving red mark only for b)32.5
c)32.5
e)102.05

Answer 12

even for
b)85 c)85 e)267.03 giving red mark

Answer 13

Vision89, assuming:
L=10H, f= 0.25hz, t= 9s
vc= -15.7079632679

Answer 14

how to find b, c , & e
plz tell the procedure with formula