Question

Can you please answer this? question is attached

Answer 1

Do you understand the basic relations of the trig functions?

Answer 2

yes

Answer 3

If you look at one of the choices marked it basically says that
sin(x) = 1/cos(x)... which I doubt is true.

I would suggest that you draw the triangle on you own and with what is given to you find out which trig function you can actually use. It only gives you 2/3 sides.

Answer 4

ok

Answer 5

so i am looking for d

Answer 6

yes and you will have some trig function f(x) such that

\[f(x)= \frac{d}{a}\] and if you want to get d by itself you would just multiply both sides by a.
$$ af(x) =d$$

Answer 7

so i would choose sec?

Answer 8

so sec(x)= d/20

Answer 9

does
\[ \sec(x) = \frac{d}{r}\]
?

Answer 10

yes, so how would you solve for d to finish?

Answer 11

so

Answer 12

\[20 \sec (x)= d\]

Answer 13

$$\checkmark$$

Answer 14

thanks

Answer 15

can you help me with one more problem?

Answer 16

sure

Answer 17

thanks let me take a screen shot

Answer 18

Ok for the rpm of the saw, I believe that you need to compute the ratio of the perimeters of the circle.
100 rpm on a perimeter of 10 meters would cause 1000 rpms on a perimeter of 1 meter.
so you need to find the perimeters first.

Answer 19

ok

Answer 20

the part b) I would imagine the motor moving one way with arrows (draw them on the cables too) and then see which way the saw has to move.

Answer 21

ok

Answer 22

i still have no idea how to answer part a

Answer 23

Ok, calculate the perimeter of the motor circle and the saw circle.
P = 2 pi r

Answer 24

so i go 30pi and 89pi for the circumference for each circle

Answer 25

94.248 and 270.176

Answer 26

cool. now the 30 pi perimeter is rotating at 2200 rotations per minute (that's what rpm means) so that in 1 minute it moves (2200)30 pi length of cable. Which has to equal (Xrpmsaw)(89Pi). Can you solve for Xrpmsaw?

Answer 27

oh ok

Answer 28

I have to leave, so I hope this helped a little. Good luck!

Answer 29

it did! thank you! Now i can go to college!!!! Im not kidding this assignment will save my grade