Can someone help me step by step? :) I have the question attached, it's a picture and #6.
Can.We.See.The.Question?
absolute min or max: on domain local: around a region absolute max: x=0+1/infinity (highest point on the graph is at x=0, but the point is excluded, so its the next point to the right, which means we need to add the smallest value of x) absolute min: x=4 (lowest point of the graph)
when a max or min appears, there is a change in the sign of the derivative. at the max or min point, therefore, the derivative = 0. this means we have 3 local min and 2 local max (absolute max and min are also local)
Uhm, I need like step by step to figure it out. Not just telling me it. I don't understand this topic, which means I need it explains in bits and slow, not chunks.. please lol?
ok, sorry, went too fast
the max point of a function is the highest value of y that an x can get. means that the maximum is the most high point of the graph. same for min, it is the lowest. the highest value on the graph is at x=0. however, there is an empty dot, which means that this point is not included in the function g(x). So, we need the closest point to x=0. we need to add the smallest number possible to x so it is nearer the 0. the smallest number is an infinitely small number, which could be written as \[1/\infty \]
okay.. So, would the abs max not exist? or is it 1/infinity.
which problem are you doing?
Number 6.
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