Question

HGFE x4= EFGH What number does each letter stand for? Is it zero for all.

Answer 1

how about 2178 :-)
The trick is how to get at that answer

Answer 2

Wow. How?

Answer 3

well, you can start by looking at H.

H*4 must be < 10 (otherwise the rhs would be 5 digets)
So H is either 0, 1, 2.
If H is 0 then the whole things breaks down to 0000
H cannot be 1 as E*4 cannot be odd.
So non-trivially H must be 2

We know that H*4 is the lower bounds for E.
Thus E must be 8 or 9.
We also know that E*4 mod 10 is 2
so E must be 8

.....

Answer 4

I'm reading

Answer 5

Would u mind finishing please

Answer 6

since h is 2 and e is 8 we know that
g*4 cannot be more than 9 as that would result in a carry.
thus g is 0,1,2

we know that since e is 8 that e*4 results in a 3 carry.

f*4 is even and with a 3 carry will be odd. That tells us
that g cannon be even.

Thus we now know that g is 1

f*4 + 3 thus ends in a 1 and it follows that f*4 must end in an 8

that makes f 7

HGFE
2178

Answer 7

That's awesome. Your great. Thank so much.