phil has 50 nickles and dimes worth $4.15. how many dimes does he have?

Question

anonymous · Answer

$10x+5(50-x)=415$ if the number of dimes is $x$

anonymous · Answer

Your Answer:
 Laura. . . it looks like the answer of "daSVgrouch" is incorrect. Here is the correct answer for you:
 
Let n = number of nickels
 Let d = number of dimes
 
The total of our individual nickels and dimes, is 50. So:
 
n + d = 50
 
Also, we know that our total in money is 415 cents.
 
5n + 10d = 415
 
So, we have 2 equations.
 
n + d = 50 (equation 1)
 5n + 10d = 415 (equation 2)
 
We can use addition, subtraction, or substitution. 

-5n + -5d = -250 (equation 1 multiplied through by "negative 5")
 5n + 10d = 415
 
Now add the two equations. . . 

0n + 5d = 165
 
Simplify. . . 

5d = 165
 
d = 33
 
If d = 33 and we have 50 total coins, then n = 17.
 
He has 33 dimes.

Source(s):

I used to teach mathematics in high school.

anonymous · Answer

dimes are worth ten cents each, and if there are a total of 50 coins and $x$ dimes then there are $50-x$ nickles worth 5 cents each. 
you have a total of 415 cents so set 
$$10x+5(50-x)=415$$solve for $x$

babystar16 · Answer

thank u again im in geomerty and math models in high school right now and i need help badly

anonymous · Answer

can you solve this equation?  or do you  still need help with it?