The circle given by
x^2+y^2-2y-11=0

can be written in standard form like this:
x^2+(y-k)^2=12
.
What is the value of k in this equation?

Question

The circle given by
x^2+y^2-2y-11=0

can be written in standard form like this:
x^2+(y-k)^2=12
.
What is the value of k in this equation?

anonymous · Answer

x² + (y² - 2y + ??) = + 11
 
(1/2)*(-2) = (-1) ; (-1)² = 1......Add 1 to both sides
 
x² + (y² -2y + 1) = 11 + 1
 
x² + (y - 1)² = 12
 
ANSWER....k = 1
 
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