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Calculus1
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find d^2y/dx^2 of y^2=9x^2+8x
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@pclende Should you try the first derivative?
This is asking for the second derivative of y^2=9x^2+8x 1. Take the first derivative: 2y dy/dx = 18x + 8 solve for dy/dx: dy/dx = (18x+8)/2y 2. Take the second derivative since we already know what dy/dx is: using the quotient rule: d^2y/dx^2 = (18(2y) - 2dy/dx(18x+8))/(2y)^2 Simplify: (36y - (36x+16) dy/dx) / 4y^2 since we already know what dy/dx is, plug it in (it easier to see this with a drawing, one second.
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