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\[given that \sin \Theta = .65 and \Theta is \in quadrant I, what is value of \tan \Theta?\]
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find cos theta from sin^2 theta + cos^2 theta =1 then tan theta = sin theta / cos theta
ohh okay, just not sure how this was started...
but yes i will work it..
ok, tell me what u get for cos theta....when u get it.
.35?
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how ? no.
what is sin^2 theta = ?
would that just be .65^2?
or am i working this wayyy wrong haha
sin^2 theta = 0.65^2 is correct so what will be cos^2 theta from the formula ?
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okay let me see
i get .76
yes, that is cos theta = 0.76 correct now find tan theta
.86?
0.8552 or 0.86 yes, thats correct
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you rock! Thanks for the help
welcome ^_^
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