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Trigonometry 6 Online
OpenStudy (anonymous):

\[given that \sin \Theta = .65 and \Theta is \in quadrant I, what is value of \tan \Theta?\]

hartnn (hartnn):

find cos theta from sin^2 theta + cos^2 theta =1 then tan theta = sin theta / cos theta

OpenStudy (anonymous):

ohh okay, just not sure how this was started...

OpenStudy (anonymous):

but yes i will work it..

hartnn (hartnn):

ok, tell me what u get for cos theta....when u get it.

OpenStudy (anonymous):

.35?

hartnn (hartnn):

how ? no.

hartnn (hartnn):

what is sin^2 theta = ?

OpenStudy (anonymous):

would that just be .65^2?

OpenStudy (anonymous):

or am i working this wayyy wrong haha

hartnn (hartnn):

sin^2 theta = 0.65^2 is correct so what will be cos^2 theta from the formula ?

OpenStudy (anonymous):

okay let me see

OpenStudy (anonymous):

i get .76

hartnn (hartnn):

yes, that is cos theta = 0.76 correct now find tan theta

OpenStudy (anonymous):

.86?

hartnn (hartnn):

0.8552 or 0.86 yes, thats correct

OpenStudy (anonymous):

you rock! Thanks for the help

hartnn (hartnn):

welcome ^_^

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