............... DP
huh? :D
dadadadaaaadadaadaaddadaa
so what shall we do.. i still cant find it :P
stop pretending , put up your questions now
hahaha... no im not, seriously i cant find it :(
question?
well, i guess i will just work on something else in math, i will do that when i find it :P
okay next science
that powerpoint? i am going to do that tonight :)
huh
hehe.. yes :)
@LonelyandForgotten here
here it is :P
wait a sec :)
sure :D
okay.. :P
haha this is funny :D
lol i am editing it, there are some grammatical mistakes, like in third slide, there should be comma after well
sure, edit it the way you like :)
yea yea :D
:)
here is your edited one, it is brilliant and indeed you are genius, just a few minor changes are there
oh thanks! :D
first read it
and find the places where i have done editing
yes i can see some :D
now maths lol
@LonelyandForgotten finally no maths, okay great
yep, no maths today :P
okay
can you help with ordered pairs? :/ thats easyy stuff, i cant do that :D
post your question please
can *
then post what you can't
okay well one is.. Determine whether the ordered pair (2, 15) is a solution of y = 4x - 7.
put the value of x=2 and y=15 if this satisfies the equation then it is a solution else it is not like y=15, x=2 15=4*2-7 15 can't be equal to 8-7 which is 1 so as 15 can't be =1 therefore it is not a solution of this y=4x-7
umm..okay i think i got that :D
next
umm this... :D A plumbing company charges $50 for a service call and $15 per hour. They went on a 3-hour job. How much did the company earn? A. $195
sorry.. A. $195 B. $165 C. $95 D. $65
well, $50 is charge and extra of $15 per hour so for three hours it will be $15*3=$45 and $50 is service call charge so total of $50+$45=$95 okay?
hmm... wait a sec :D
sure , next please
most of the questions are like this, Determine whether the ordered pair (5, 3) is a solution of y = 3x – 4. .... i just wanna know how to solve those :/
look in all these equations just put x=5 and y=3 actually the content of bracket (5,3) are the values of x and y (x,y) now if putting x=5 and y=3 in the equation y=3x-4 satisfies then it is a solution else not now put x=5 and y=3 3=3*5-4=15-4=11 3=15-4 which is not correct if we would have obtained 3=3 then it must be the solution but we got 3=11 which is false so its not a solution
clear?
i dont get it :/ where did the 15 and 11 come from?
@LonelyandForgotten ??
i am here.. :D
well at the place of x in the equation put x=5 and at y put y=3 now y=3x-4 put y=3 and x-5 3=3*5-4 ------------ 3*5= 15 3=15-4------------15-4=11 3=11 this is false , clear?
okay it seems confusing but i will go over this a few times later, but thanks :)
just put y= its value and x= the value of x as in ordered pair in the equation and if both the sides are equal you will have it as solution else no
and this will help you more i guess http://www.virtualnerd.com/pre-algebra/algebra-tools/test-ordered-pair-equation-solution.php
next?
please can we stop for now.. i dont wanna do this :(
one more
umm.. are you sure? :D
hahah am i sure come on keep asking
This is Last one.. please 7. Use a table of solutions to find the ordered pair solution for y = 4x – 6 when x = 10. A. (34, 10) B. (10, 34) C. (10, 8) D. (8, 10)
no after this you're gonna do it unless you're finished :)
nope im not even close to being done :P
if we put x=10 in the equation y=4x-6 we will get y= 4*10-6 , just at the place of x put x=10 y=40-6 y=34 therefore your ordered pair is (10,34) which means when x=10 , y=34 clear?
yes clear! :P
hmm next ? unless you are finished
yes i am finished, now thanks! :P lol
actually no.. sorry :)
next
question ? :)
wait please :(
okay :)
this :D
whats a quadric eqaution?
or quadratic* sorry
quadratic equations are those whose degree is two like the equation in which maximum power of x is 2 and minimum too like \[x^2+x+2=0, x^2+1=0, x^2=0\] equations in which power of x is two are quadratics ,so this type of equations are not quadratic , \[x+1=0, x^3+3x^2+x+3=0\] in quadratic power of x must be 2
so your answer is option D cuz its cubic x has power 3 clear?
hmmm.. alright :)
next
whats a parabola?
its a conic section, created from the intersection of a right circular conical surface and a plane parallel to a generating straight line of that surface. like consider this |dw:1353988143775:dw| its a parabola and every quadratic equation represents a parabola so all the equations with degree two which means power of x should be 2 represents a prabola
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