line AB contains points (2,1) and (-1,-8). What is the equation of the line parallel to line AB that contains point (0,2)?

Question

anonymous · Answer

First, get the slope of line AB:$$\frac{ y _{1}-y _{2} }{ x _{1}-x _{2} } = m$$ where "m" is the slope and (x1, y1), and (x2, y2) are the points given in AB.

anonymous · Answer

Next, the equation of the parallel line is:$$y - y _{1} = m(x - x _{1})$$where (x1, y1) is the point (0, 2).  This is the point-slope equation of the line.  The line can be put into other forms from this equation, including the standard form and the slope-intercept form.

anonymous · Answer

i just plug those into the equation

anonymous · Answer

Well, there are 2 equations, one for each of my previous posts.  You have to start with getting "m" which is the slope.  Yes, make substitutions.

anonymous · Answer

ok, i got it now. now that I have seen the equaions. thanks

anonymous · Answer

yw!