. Write the equation of a line in slope-intercept form that is perpendicular to the line and passes through the point (-9, 4)
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OpenStudy (anonymous):
OpenStudy (anonymous):
@AriPotta
OpenStudy (anonymous):
@AriPotta
OpenStudy (anonymous):
i dnt know?
OpenStudy (anonymous):
go
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OpenStudy (aripotta):
what's going to be our slope?
OpenStudy (anonymous):
der i press it
OpenStudy (aripotta):
yep, it worked :)
so what's our slope lol
OpenStudy (anonymous):
m=y-1 x2-x?
OpenStudy (aripotta):
what's the slope of the given line?
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OpenStudy (anonymous):
y=3/5 x-1
OpenStudy (aripotta):
the slope. what's the slope?
OpenStudy (aripotta):
:l the slope is either 3/5 or -1, which is it?
OpenStudy (anonymous):
3/5
OpenStudy (aripotta):
yes, so if a new line is perpendicular to this one, what's going to be the slope of the new line?
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OpenStudy (anonymous):
3/5?
OpenStudy (aripotta):
no, that would make the new line parallel, not perpendicular. perpendicular lines have negative reciprocal slopes of each other. so our new line would have a slope of...?
OpenStudy (anonymous):
-1?
OpenStudy (aripotta):
sigh
OpenStudy (anonymous):
lol
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OpenStudy (aripotta):
it would have a slope of -5/3
OpenStudy (aripotta):
we basically just flipped the numerator and denominator and made it negative
OpenStudy (anonymous):
oh lol
OpenStudy (aripotta):
ok. so we have our slope: -5/3 and it goes through point (-9,4). what would our equation be in point-slope form?
OpenStudy (anonymous):
x-4/y-+4?
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OpenStudy (aripotta):
no. point-slope form is y - y1 = m(x - x1)...
OpenStudy (anonymous):
y-4=m(x-9)
OpenStudy (anonymous):
add 4 y=mx-5
OpenStudy (aripotta):
stop. you didn't substitute for m
OpenStudy (aripotta):
m = slope. what's our slope?
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OpenStudy (anonymous):
-5/3
OpenStudy (aripotta):
and, it +9, not -9
OpenStudy (aripotta):
it's*
OpenStudy (anonymous):
ok now wat
OpenStudy (aripotta):
y - 4 = -5/3(x + 9)
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OpenStudy (aripotta):
distribute the -5/3
OpenStudy (anonymous):
omg how do i do tht lol
OpenStudy (aripotta):
sigh
OpenStudy (aripotta):
9/3 = ?
OpenStudy (anonymous):
3/1
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OpenStudy (aripotta):
or just 3 lol
OpenStudy (anonymous):
lmao slap myself
OpenStudy (aripotta):
and 3(-5) = ?
OpenStudy (anonymous):
-15
OpenStudy (aripotta):
right, so....
y - 4 = -5/3x - 15
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OpenStudy (anonymous):
add 4 ?
OpenStudy (aripotta):
yes
OpenStudy (anonymous):
-11
OpenStudy (aripotta):
y = -5/3x - 11
OpenStudy (anonymous):
yupp
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OpenStudy (anonymous):
ahhhh my test is almost over can u give me the answer 4 this pretty please im ur fan already <33
. What is the first step of constructing a perpendicular line from a point not on a given line? (Points : 2)
Without changing the compass, from each intersecting arc on the line, construct two arcs on the side opposite the given point.
Draw a line from the point to the intersecting arcs.
From the point not on the line stretch the compass and mark two arcs on the line.
Use your ruler and draw a straight line from the point through the line.