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Mathematics 7 Online
OpenStudy (anonymous):

. Write the equation of a line in slope-intercept form that is perpendicular to the line and passes through the point (-9, 4)

OpenStudy (anonymous):

OpenStudy (anonymous):

@AriPotta

OpenStudy (anonymous):

@AriPotta

OpenStudy (anonymous):

i dnt know?

OpenStudy (anonymous):

go

OpenStudy (aripotta):

what's going to be our slope?

OpenStudy (anonymous):

der i press it

OpenStudy (aripotta):

yep, it worked :) so what's our slope lol

OpenStudy (anonymous):

m=y-1 x2-x?

OpenStudy (aripotta):

what's the slope of the given line?

OpenStudy (anonymous):

y=3/5 x-1

OpenStudy (aripotta):

the slope. what's the slope?

OpenStudy (aripotta):

:l the slope is either 3/5 or -1, which is it?

OpenStudy (anonymous):

3/5

OpenStudy (aripotta):

yes, so if a new line is perpendicular to this one, what's going to be the slope of the new line?

OpenStudy (anonymous):

3/5?

OpenStudy (aripotta):

no, that would make the new line parallel, not perpendicular. perpendicular lines have negative reciprocal slopes of each other. so our new line would have a slope of...?

OpenStudy (anonymous):

-1?

OpenStudy (aripotta):

sigh

OpenStudy (anonymous):

lol

OpenStudy (aripotta):

it would have a slope of -5/3

OpenStudy (aripotta):

we basically just flipped the numerator and denominator and made it negative

OpenStudy (anonymous):

oh lol

OpenStudy (aripotta):

ok. so we have our slope: -5/3 and it goes through point (-9,4). what would our equation be in point-slope form?

OpenStudy (anonymous):

x-4/y-+4?

OpenStudy (aripotta):

no. point-slope form is y - y1 = m(x - x1)...

OpenStudy (anonymous):

y-4=m(x-9)

OpenStudy (anonymous):

add 4 y=mx-5

OpenStudy (aripotta):

stop. you didn't substitute for m

OpenStudy (aripotta):

m = slope. what's our slope?

OpenStudy (anonymous):

-5/3

OpenStudy (aripotta):

and, it +9, not -9

OpenStudy (aripotta):

it's*

OpenStudy (anonymous):

ok now wat

OpenStudy (aripotta):

y - 4 = -5/3(x + 9)

OpenStudy (aripotta):

distribute the -5/3

OpenStudy (anonymous):

omg how do i do tht lol

OpenStudy (aripotta):

sigh

OpenStudy (aripotta):

9/3 = ?

OpenStudy (anonymous):

3/1

OpenStudy (aripotta):

or just 3 lol

OpenStudy (anonymous):

lmao slap myself

OpenStudy (aripotta):

and 3(-5) = ?

OpenStudy (anonymous):

-15

OpenStudy (aripotta):

right, so.... y - 4 = -5/3x - 15

OpenStudy (anonymous):

add 4 ?

OpenStudy (aripotta):

yes

OpenStudy (anonymous):

-11

OpenStudy (aripotta):

y = -5/3x - 11

OpenStudy (anonymous):

yupp

OpenStudy (anonymous):

ahhhh my test is almost over can u give me the answer 4 this pretty please im ur fan already <33 . What is the first step of constructing a perpendicular line from a point not on a given line? (Points : 2) Without changing the compass, from each intersecting arc on the line, construct two arcs on the side opposite the given point. Draw a line from the point to the intersecting arcs. From the point not on the line stretch the compass and mark two arcs on the line. Use your ruler and draw a straight line from the point through the line.

OpenStudy (anonymous):

@AriPotta

OpenStudy (aripotta):

it's either c or d

OpenStudy (anonymous):

thnks 4 everything love stay AWESOME :D

OpenStudy (aripotta):

lol you're welcome

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