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a(x+7) + b(x+5) = x+1 Find a - b
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\[\Huge x(a+b) + 7a + 5b = x+1\]Now what?
the constants are equal; the coefficients of x are equal, that is \[\huge 7a+7b=1\] \[\huge a+b=1\]
correction: the first equation is \[\huge 7a+5b=1\]
And a+b = 1 too?
yes, that's right.
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So a - b = -5?
yup.
Well, that was easier than I excepted, but what if I have something like this: x(a+b)+7a+5b= -1(x+1)
-(a+b) = 1 -(7a + 5b) = 1 Right?
@sirm3d
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right. just compare coefficients of x and constants.
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