Everybody in a room shakes hands with everybody else.the total number of handshakes is 66.Then the total number of persons in the room is :
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OpenStudy (hba):
only hints
hartnn (hartnn):
for 2 ppl, handshakes = 1
for 3 people . handshakes = 1+2
for 4 people, handshakes = ?
OpenStudy (hba):
1+2+3
OpenStudy (hba):
@hartnn
OpenStudy (anonymous):
12 person in meeting
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OpenStudy (hba):
I have reported you ^
hartnn (hartnn):
so continuing that way, could u generalize it ?
hartnn (hartnn):
for n ppl , 1+2+3+...n-1 = ?
OpenStudy (hba):
Ok so how does this help
hartnn (hartnn):
for n ppl, it will be n(n-1)/2 = 66
find n
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OpenStudy (hba):
So where did you get n(n-1)/2 from ?
hartnn (hartnn):
1+2+3+4+.....n = sum of n numbers = n(n+1)/2
standard formula
OpenStudy (hba):
Thanks Alot.
OpenStudy (hba):
Here you have written n(n+1)/2 ?
hartnn (hartnn):
yes, for n
for n-1 ?
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hartnn (hartnn):
just replace n by n-1
OpenStudy (hba):
Ok so (n-1)(n+1)/2
hartnn (hartnn):
no
OpenStudy (anonymous):
suppose in a room n person are there.now two person make one hand shake.means total shake hand is C(n,2),but we are given total shake hand 66.solve C(n,2)=66 we have 12
hartnn (hartnn):
(n-1)(n-1+1)/2
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OpenStudy (hba):
oh ok ok i got it now :) Thank you. let me find the answer.
OpenStudy (hba):
n(n-1)/2=66
OpenStudy (anonymous):
right
hartnn (hartnn):
ya, solve that
OpenStudy (anonymous):
12 right
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OpenStudy (hba):
So i got n^2-n-132=0
hartnn (hartnn):
go on
OpenStudy (hba):
ok i am trying
OpenStudy (anonymous):
minus 12 and plus 11 solve this
OpenStudy (hba):
n=-11 and n=12
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