factor the trinomial completely ........25x^3-55x^2-60x
take 5x out as a common factor 1st 5x(5x^2 - 11x - 12) next factor the trinomial in the brackets.
@campbell_st, how would I do that there are no GCF for 5x^2-11x-12...I'm confused
@campbell_st, how would I do that there are no GCF for 5x^2-11x-12...I'm confused
here is my method for a trinomial like this or any quadratic in the form ax^2 + bx + c multiply a and c 5 x -12 = -60 find the factors of -60 that add to - 11...
are you able to find the factors..?
give me a sec
10 and 1?
then it is |dw:1352663021174:dw| you'll find that there are common factors in the numerator that will cancel in the denominator.
10 x 1 = 10 find 2 numbers that multiply to -60 and add to -11 try 6 x -10 = -60 6 + -10 = -4 not them 3 x -20 = -60 3 + -20 = -17 not them 5 x - 12 = -60 5 + -12 = -7 not them any ideas..?
oh multiply ok I missed that some kind of way
ok... I got nothing... I cant think of anything that would be multiplied to get 60 and added to get 11
well you need something between 3 x -20 and 5 x - 12... any thoughts...?
im sorry..I'm thinking about it
sorry...I have no idea what I'm looking for here...I dont know what's in between 3x-20 and 5x-12.. i just dont get this
try 4 and - 15.... so you have |dw:1352663658344:dw| the solution for the trinomial is done... all you need to do is combine the solution.
ok I kind of understand
so first i look for GCF then divide it by that?
what do u mean combine it
5x(x -3)(5x + 4)
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