Guys need help please... Solve for x: √(5x-4)=x/2+2
First Raise both sides to the power of two: \[5x-4=(x/2+2)^2\] expand terms on right side: \[5x-4=(x^2/4)+2x+4\] move everything to left side: \[(-x^2/4+3x-8)=0\] the left hand side factors into: -1/4((x-8)(x-4))=0 multiply both sides by -4 (x-4)(x-8)=0 So the two answers are x =4 and x=8.
Note that you'll have to restrict the domain of the function and check if the answer are in the domain after you solve it.
Both of those are in the domain.
:) Then there's nothing wrong. Sorry, it's a habit I got from my strict math teacher.
Oh no need to apologize, I went back and checked it after you said that.
lol Maths is fun.
Thank you!! ((:
Can I have a medal?
sure! but how can i give it to you?
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