Question

Find the intervals of concavity and points of inflection of y=(4-x^2)^5
I have already found the first derivative to be -10x(4-x^2)^4 but I am stuck on finding the second derivative . . . Wolfram Alpha keeps saying I am wrong and I have no idea why.

Answer 1

y=(4-x^2)^5

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y'=5(4-x^2)^4*(-2x)

y' = -10x(4-x^2)^4

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y'' = -10(4 - x^2)^4 + (-10x)*(4)*(4-x^2)^3*(-2x)

y'' = -10(4 - x^2)^4 + 80x^2(4-x^2)^3

Answer 2

Thanks for some reason I wrote down 2x^2 as the derivative of x^2

Answer 3

yw