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Given f(x)=2x^2+x-3 and g(x)=x-1 a.(f o g)(x) b.(g o f)(x)
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For a) You need to "insert" (x-1) everywhere you see an X in f(x). Expand and simplify.
So (fog)(x)=2(x-1)^2+(x-1)-3
Let me know how it turns out. Then we can do part B.
@onmng314 its correct
Cool. For (gof)(x) You need to "insert" 2x^2+x-3 everywhere you see an X in g(x).
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Thus, (gof)(x)=(2x^2+x-3)-1 All we did is "insert" or "substitute" an entire function into another function for X to make a composition. I think you can finish (gof)(x). Let me know.
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