Question

Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it.
lim sin x ln 4x
x→0+

Answer 1

I tried re-writing it as \[\frac{ \ln 4x }{ \csc x }\]
but the derivative of csc is always going to have csc in it and csc 0 is 1/sin 0 which is 1/0 no matter how many derivatives i take