Question

Find the zeros for P(x) = 2x^3 - 7x^2 - 15x

Answer 1

@odehye We have to find the solution of this
\[2x^3-7x^2-15x=0\]
Take x common
\[x(2x^2-7x-15)=0\]
Now we have
\[x=0\ \text{or}\ (2x^2-7x-15)=0\]
So one root is zero
Can you solve this quadratic equation to find the other two roots ?
\[2x^2-7x-15=0\]

Answer 2

Do you get this part @odehye ?

Answer 3

yes, i did

Answer 4

Can you solve the quadratic to find the other two roots?

Answer 5

i'm lost

Answer 6

using P/Q theorem

Answer 7

The easiest way is to us the quadratic formual to solve for zeros.

Answer 8

x=5 and x=-3/2

Answer 9

@ash2326 x=x=5 and x=-3/2