Question

Solve by using the quadratic formula x^2 + 6x = -3

-3±√-3?

Answer 1

rewrite the equation

x^2 + 6x + 3 = 0

then the gneral quadratic formula is

\[\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

you have a = 1, b = 6 and c = 3

just substitute and evalaute

Answer 2

x^2 + 6x = -3

x^2 + 6x + 3 = 0

Answer 3

-3±√6?

Answer 4

@campbell_st am i right?

Answer 5

looks correct to me... I just did it as mental arithmetic...

Answer 6

:) thanks