Question

Solve x2 + 6x + 7 = 0.

Options are below!!!

Answer 1

know quadratic formula ?

Answer 2

Compare your quadratic equation with \(ax^2+bx+c=0\)
find a,b,c
then the two roots of x are:
\(\huge{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)

Answer 3

\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 4

How do I apply that to this problem? Like i'm having trouble setting it up

Answer 5

none of the options are correct
b^2-4ac = 36-28 = 8
so there should be sqrt 8 in options or sqrt 2

Answer 6

couldn't u find, a,b,c ?

Answer 7

Those are the only options.......

Answer 8

then your question must be incorrect

Answer 9

check it

Answer 10

also see your previous question

Answer 11

for this its,
(-6+- sqrt 8)/2 = (-3+- sqrt2)

Answer 12

Solve x2 + 6x + 7 = 0

Answer 13

for that (-3+- sqrt2)

Answer 14

Oh my goodnes!!!!1 I'm SO sorry

Answer 15

i see what occurred

Answer 16

the question is: Solve 3x2 + 4x = 2

Answer 17

right,
3x^2+4x-2=0
now apply the formula
can u find,a,b,c first ?

Answer 18

3, 2, 4?