Question

how do I compute 4^n*2^(n+1) ?

Answer 1

what is the value of n?

Answer 2

there is no value of n it's just a variable... wolfram says it's equal to 2^3n+1 but does gives out the steps...

Answer 3

that is because \(4=2^2\) and so \(4^n=2^{2n}\)

Answer 4

therefore when you add the exponents you get
\[2^{3n+1}\]

Answer 5

You need to simpify the exponents then?

Answer 6

ohhhh !! I see ! thank you for your help !