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Find a polynomial of degree 3 that has zeros 1, -2, and 3, and in which the coefficient of x^2 is 3.
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(x-1)(x+2)(x-3) = 0
expand and multiply the result by the number that gives a coefficient of '3' on the x^2 term...
How do you get the coefficient of x^2 to be 3 though?
x^3 -2x^2 -5x +6 = 0 (-3/2)(x^3 -2x^2 -5x +6 = 0)
Where did you get the -3/2 from?
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...
-2*-3/2 =3
I got up to that part and then i got stuck
Oh okay thank you so much!
sure:)
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