Question

A discriminant of 0 indicates what type of roots?



Two Irrational

Two Complex

Two Rational

One Rational Double


(One real root.

If the coefficients of the quadratic are rational then it will be a rational root)

Answer 1

your answer is...

Answer 2

\[ax^2+bx+c=0\] gives \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] if \(b^2-4ac=0\) you get only
\[x=-\frac{b}{2a}\] i.e.the first coordinate of the vertex, meaning you have a perfect square
like say \((x-3)^2\)
one rational double zero

Answer 3

D) one rational double

Answer 4

My answers D, i said it already ;)

Answer 5

One real root.

Answer 6

yep :)

Answer 7

thank you so much :) @Valkarie70