8.07] Jose factored 27x2 + 48y2 using the following steps.

27x2 + 48y2 = 3(9x2 + 16y2)
= 3(3x + 4y)(3x − 4y)

Determine whether Jose factored this binomial correctly. If not, use complete sentences to explain what he did wrong and how he could check his factors for accuracy in the future.
Please tell me what he did wrong and also tell me how the correct way to solve this problem is?

Question

8.07] Jose factored 27x2 + 48y2 using the following steps.

27x2 + 48y2 = 3(9x2 + 16y2)
                   = 3(3x + 4y)(3x − 4y)

Determine whether Jose factored this binomial correctly. If not, use complete sentences to explain what he did wrong and how he could check his factors for accuracy in the future. 
Please tell me what he did wrong and also tell me how the correct way to solve this problem is?

anonymous · Answer

he factored it wrong lol

anonymous · Answer

LOL, that much I got!!! ;)

anonymous · Answer

he did it wrong after he reduced it from 27 to 9 and 48 to 16

anonymous · Answer

OMG< thx so much, you r a lifesaver!!

anonymous · Answer

wait

anonymous · Answer

it isn't factorable past that point lol

anonymous · Answer

LOL, thx. That's it right?

anonymous · Answer

well yeah because its a sum of squares not a difference of squares...

anonymous · Answer

you cant factor past the answer unless it were a difffernece of squares, for example 9x^2-16y^2=(3x + 4y)(3x − 4y)