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OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
@campbell_st last one I promise!
OpenStudy (campbell_st):
ok...do you know how to find the intercepts of the line
-4x + 7y = -28...?
OpenStudy (anonymous):
is it 7y=4x-28
y=mx+b form right?
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OpenStudy (anonymous):
@campbell_st
OpenStudy (anonymous):
(C)
OpenStudy (campbell_st):
thats correct... well done
OpenStudy (campbell_st):
for intercepts
-4x + 7y = -28 let x = 0 to find the y intercept
7y = -28 so y = -4 point is (0, -4)
for x-intercept left y = 0
-4x = -28
so x = 7 point (7, 0)
so find the graph where the line goes through (7, 0) and (0, -4)
OpenStudy (anonymous):
thanks I wasn't sure if you plug in the 0's or not
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OpenStudy (anonymous):
@haleycoulter just remember in graphs simple way is to find x-intercept and y-intercepts i.e the points at x-axis and y-axis through which line passes:)
so at x-intercept y=0
and at y-intercept x=0
put in equation try it...............:)