Question

Consider the eddy-current braking. A square loop, with 10 cm side is shot with the velocity 10 m/s into the uniform magnetic field with magnitude 0.1 T. The field is perpendicular to the plane of the loop, and the loop starts entering magnetic field at t=0. The resistance of the loop is 1.00 Ohm and the mass is 1.0 g. Assume the loop is moving to the right along x-axis and that x(t=0)=0. Find the velocity of the loop 0.1 seconds later.

Answer 1

The equation of motion is x(t)=C1+C2*exp(-K*t)
where C1=v0/K C2=-v0/K and K=B^2*s^2/(m*R)

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