Question

how do you solve ln6-lne^2

Answer 1

\[\log_e6-\log_ee^2=\log_e6-2\]
\[ln6\]I have no idea how to work it out without a calculator (series expansion maybe...)

Answer 2

Thanks anyways!

Answer 3

\[ \ln6-lne^2=\ln\frac{6}{e^2}\] This doesn't really help either

Answer 4

Yeah that was the original version of the question, \[lne^2\] equals 2, I just don't know what to do about the ln6