Question

determine that each equation is an identity.

(cscX-cotX)^2=1-cosX/1+cosX

Answer 1

do for left side, gives :
(cscx-cotx)^2 = (1/sinx - cosx/sinx)^2 = ((1-cosx)/sinx)^2
for right side, gives :
(1-cosx)/(1+cosx) * (1-cosx)/(1-cosx)
= (1-cosx)^2 * (1+cosx)(1-cosx)
= (1-cosx)^2 * (1-cos^2 x)
= (1-cosx)^2 * sin^2 x
= ((1-cosx)/sinx)^2

Answer 2

does this make sense ?

Answer 3

im still figuring it out... but i'm "starting" to understand...

Answer 4

oke

Answer 5

on the right side, why did you do this: (1-cosx)/(1+cosx) * (1-cosx)/(1-cosx)?

Answer 6

oh never mind i understand :)