Question

show that sin(theta)+cos(theta)+tan(theta)sin(theta)=sec(theta)+cos(theta)tan(theta)

Answer 1

please help.... :(

Answer 2

let me use x instead of theta
then LHS = sinx+cosx +sinxtanx=sinx+cosx +(sinx/cosx) sinx
=sinx+cosx +(sin^2x)/cosx =sinx+(cosx +(sin^2x)/cosx)
=sinx +(cos^2x+sin^2x)/cosx=sinx +secx
=sinx.cosx/cosx + secx =
=cosx(sinx/cosx) +secx =cosxtanx +secx= sec(theta)+cos(theta)tan(theta) [as i have used theta as x]

Answer 3

what is LHS?

Answer 4

LHS is left hand side of the question

Answer 5

ooh ok thank you so much!

Answer 6

welcome