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MIT 6.002 Circuits and Electronics, Spring 2007 8 Online
OpenStudy (anonymous):

H11P1: LC Tank Parallel resonant "tank" circuits are common in radio equipment. But unfortunately there is always resistance that prevents them from being perfect: in every real inductor, the wire that makes up the inductance has some resistance, and there may be leakage in the capacitor that can be modeled as a resistance. Also, the Norton resistance of the system connected to the tank circut looks like a leakage through the capacitor. So a realistic model for a tank circuit is the following: In the space provided below write an algebraic expression in terms of the device parameters for t

OpenStudy (anonymous):

value of C?

OpenStudy (anonymous):

The antenna tank of a Graymark 536 Radio Kit has an inductance L≈0.65mH. The resistance of the inductor RL≈4.0Ω. The equivalent resistance across the capacitor is RC≈490.0kΩ. The capacitor is variable, for tuning. If we tune to a station at f=740.0kHz what is the capacitance, in picoFarads, of the tuning capacitor? incorrect What is the bandwidth, in kHz, of the tank at f=740.0kHz? incorrect If next we tune to a station at f=1570.0kHz what is the capacitance, in picoFarads, of the tuning capacitor? incorrect What is the bandwidth, in kHz, of the tank at f=1570.0kHz? incorrect So it is apparent that this is not the only circuit in the radio that selects the desired station from stations on adjacent channels.

OpenStudy (anonymous):

capacitor is variable

OpenStudy (nurali):

71.16 5-8 15.8 20-25

OpenStudy (anonymous):

only 71.16 and 15.8 are correct rest r still wrong help me

OpenStudy (anonymous):

no dey r wrong

OpenStudy (nurali):

7 23

OpenStudy (anonymous):

H11P2: Scope Probe We can model the interaction of an oscilloscope with the device under test (DUT) with the following circuit. A typical modern oscilloscope has an input resistance of Rs=1.0MΩ and an input capacitance of 12<Cs<25pF. Assume that the input capacitance of our oscilloscope Cs=16.0pF. It is connected to the circuit with a 10X probe with resistance of Rp=9.0MΩ. There is a variable capacitor, adjustable with a special tool, that is in parallel with the resistance in the probe. The device under test is modeled as a voltage source with voltage vM. If the frequency of the source being measured is very low or a DC value, for example vM=0.7V, what is the value of the voltage vS, in Volts, that the oscilloscope sees? incorrect The oscilloscope is used to measure and display waveforms at many frequencies. Suppose that VM=0.08cos(2π 130.0×106 t) V. What is the value, in picoFarads, that Cp should be set to so that Vs=0.008V? incorrect Suppose now that VM=0.4cos(2π 226.0×106 t) V. What is the value, in picoFarads, that Cp should be set to so that Vs=0.04V? incorrect Hmmmmm.... Now suppose that VM=2.0 u(t) V and suppose that just before the step, VCP(0−)=0 and VCS(0−)=0. Assume that the value of Cp is what you computed for the last question. What is the value of vS(0+), in Volts? incorrect

OpenStudy (anonymous):

still wrong

OpenStudy (anonymous):

What is the bandwidth, in kHz, of the tank at f=740.0kHz?

OpenStudy (anonymous):

22 is corrrect

OpenStudy (nurali):

4

OpenStudy (anonymous):

In the space provided below write an algebraic expression in terms of the device parameters for the bandwidth Δω of the impedance Z looking into this tank circuit. incorrect 71.16

OpenStudy (anonymous):

4 is incorrect

OpenStudy (anonymous):

h11 p1 a, and c

OpenStudy (anonymous):

a) 1/(RC*C) + RL/L

OpenStudy (anonymous):

value of c?

OpenStudy (anonymous):

c is variable in my question

OpenStudy (anonymous):

1st question needs only expression

OpenStudy (anonymous):

p1 c?

OpenStudy (anonymous):

range of dis ans is from 4 to 10 depending on ur values

OpenStudy (anonymous):

itz not working

OpenStudy (anonymous):

did u tried decimal values between 4 and 10 coz my ans is 4.3

OpenStudy (anonymous):

i have tried but i am getting wrong answer

OpenStudy (anonymous):

wats d value of f in ur C) question ?

OpenStudy (anonymous):

740khz

OpenStudy (anonymous):

ur ans for c) part is surel within the range of 5.1 to 7 chek for all d decimal values dude :)

OpenStudy (anonymous):

tnx i got it .................can u also help me in h9 boost convertor

OpenStudy (anonymous):

yes double click on square term and change the value of duty cycle to 58% and den click on TRAN option on top-left and den without closing d dialog box of transient response click on check if correct pls giv Best Response :)

OpenStudy (anonymous):

tnx dude

OpenStudy (anonymous):

lab 10 boost convertor/?

OpenStudy (anonymous):

L-1.6u C-16221910p R-10 DRAW A SERIES COMBINATION OF L-C-R n/w wid above values and join d ckt

OpenStudy (anonymous):

ac analysis is coming wrong

OpenStudy (anonymous):

click on check directly after joining d series combination wid d ckt diagram n den see

OpenStudy (anonymous):

no it s not working

OpenStudy (anonymous):

OpenStudy (anonymous):

did u put d values as above and dont put the unit by urself coz after entering d values of compnents units are given to it by-default

OpenStudy (anonymous):

c the circuit

OpenStudy (anonymous):

ckt is correct or not

OpenStudy (anonymous):

OpenStudy (anonymous):

any luck ??

OpenStudy (anonymous):

What is the bandwidth, in kHz, of the tank at f=1570.0kHz?

OpenStudy (anonymous):

@abdullatif92211 4.3

OpenStudy (anonymous):

@fettah901 sory didn't worked :)

OpenStudy (anonymous):

set the L=1.59mH and C=159nF

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