Solve for x:
(x-2)(3x+2)/(x-1)(2x+3) = -1/(x-1)
I broke it down so the denominators are the same
(x-2)(3x+2)/(x-1)(2x+3) = -(2x+3)/(x-1)(2x+3)
Now I am lost, do I distribute?

Question

Solve for x: 
(x-2)(3x+2)/(x-1)(2x+3) = -1/(x-1)
I broke it down so the denominators are the same
(x-2)(3x+2)/(x-1)(2x+3) = -(2x+3)/(x-1)(2x+3)
Now I am lost, do I distribute?

anonymous · Answer

(x-2)(3x+2)/(x-1)(2x+3) = -1/(x-1)
(x-2)(3x+2) =  -1(x-1)(2x+3)/(x-1)
(x-2)(3x+2) =  -1(2x+3)
(x-2)(3x+2) =  -2x-3
3x^2 + 2x -6x - 4 = -2x -3
3x^2 -2x - 1 =0 
(3x + 1) (x -1)

anonymous · Answer

@Jlowe  did u get it??

anonymous · Answer

Hot Dog! I thought I was wrong. So it looks like when the instructor said beware of the number you can't use, he was referring to a solution of 1. Thank you