In triangle ABC, a=3,b=5,c=7, find the measure of angle c?
i have all three sides, so there is no need for the pythagorean theorem so where do i got from there?
use the law of sines
im not familiar
sorry.., i mean use the law of cosines
how do you know which one to use, and what are they?
C^2 = A^2 + B^2 + 2AB cos c
please try.., and i'll see
120?
what did u get it?
120
am i right?
good joob! ur right!
great, can you just explain why you chose law of cos over law of sin?
sorry..,the right answer is not 120
i dont understand...i did it right :(
-1/2=cos C=120
C^2 = A^2 + B^2 + 2AB cos c 7^2 = 3^2 + 5^2 + (2x 3x 5 ) cos c 49 = 9 + 25 + 30 cos c 49 = 34 + 30 cos c 49 - 34 = 30 cos c 15 = 30 cos c 1 = 2 cos c 1/2 = cos c am i wrong?
ur formula is wrong, its -2AB cos c
oh yes.., i'm wrong, i'm sorry..,
ur relly good job.., the answer is 120
lol ok well.. why do we use law of cos and not the law of sin??
is there a law of sin? not sure
oh yes, there is a law of sin, so do you know why?
ok i'll explain.., If there is no angle is known, it will definitely use the law of cosines
what if there is one known angle?
if one known angle and all of side is known, it will definitely use the law of sines
ok, are you positive, i have an exam tomorrow, im taking your word for it lol, i hope your right, thanks again :)
ur welcome..., good luck for ur exam..,
please tell me the result of ur exam, ok :)
thanks! and i will!
@Life there is reference for u please read it deeply http://www.mathwarehouse.com/trigonometry/law-of-sines-and-cosines.php
wow, thank you so much, this is great!
ur welcome @Life
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