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Find the derivative of tan(2x-1)^2
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ok
derivative of (2x-1)^2 = 2(2x-1)*2 derivative of tan(2x-1)^2 = sec^2 (2x-1)^2 use "chain rule"
not product?
just multiply of them, gives y' = 2(2x-1)*2* sec^2 (2x-1)^2 y' = 4(2x-1)* sec^2 (2x-1)^2 y' = (8x-4)*sec^2 (2x-1)^2
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I thought it was sec2(8-4)
sec 2 from tan and then (2x-1)^2 for second part which is chain
multiplying process all derivative parts, its called chain rule
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