Question

I am kind of stuck I am not sure if this is the answer, help please...

Answer 1

the general form is

\[y = a(x -h)^2 + k \]

(h, k) is the vertex in your question the vertex is (1, -4)

to find the value of a... substitute your point (2, -2) and evaluate

Answer 2

@ campbell_st that's the part I don't get how to find a?

Answer 3

let f(x)=ax^2+bx+c
put (1,-4)
-4=a+b+c----------------------(1)
put(2,-2)
-2=4a+2b+c---------------------(2)
now 1,-4 is the least point also which is attained at x=-b/2a
so -b=2a--------------------------(3)
now 3 equations 3 unknown :)

Answer 4

@malibugranprix2000