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solve by completing te square 5x^2=7x-4
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When they say completing the square what comes to mind?
taking half of the coefficient and squaring it
coefficient of the x term
Actually, yes. You want to get everything with an x to one side: 5x^2-7x=4 The bad part about completing the square is that the x^2 has to have a coefficient of 1 so now you "get" to divide it all by 5: x^2-7x/5=4/5 Now add half the x's coeffiecent to both sides.
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