Question

solve algebraically: x-y+z=5
-2x-y-z=-6
3x+3y-2z=-5 please and thank you :)

Answer 1

Well, first you need to figure out one variable:

x-y+z=5
-2x-y-z=-6

If you subtract the second from the first what do you receive?

Answer 2

-3x-2y-2z=-11?

Answer 3

I tried this once before but it didn't work out right so now I'm unsure about my methods/math

Answer 4

You need to subtract them, you are adding them together.

Answer 5

multiply both side of 3x + 3y - 2z = -5 by -1
-3x -3y + 2z = 5
set it equal to x-y+z = 5

-3x -3y + 2z = x - y + z
4x + 2y -z = 0

for this equation -2x - y -z =-6 add 6 on both sides
-2x - y - z + 6 = 0
set the 2 equation equal to each other
4x + 2y -z = -2x - y - z +6
simplify
6x + 3y = 6
solve for x
6x = 6 -3y
x = 1 - y/3

substitute back in the equation 6x + 3y = 6
6(1 - y/3) + 3y = 6
6 - 2y + 3y = 6
y = 0
that means x = 1
and
x - y + z = 5
1 - 0 + z = 5
z = 4

Answer 6

Thank you so much! I was so stuck on that one! And thank you as well malical for your time :)

Answer 7

np glad to help