Question

another expression for sin(tan^-1x)

Answer 1

let : tan y = x/1

sin y = x/ sqrt (x^2 + 1)

sin ( sin^-1 y) = y


sin ( sin^ -1 x/ sqrt (x^2 + 1)) = x/ sqrt (x^2 + 1)

Answer 2

where is tan y= x/1 from??

Answer 3

tan x = 1

x = tan^-1 x

Answer 4

sorry x = tan^-1 1

Answer 5

can you please explain it in easier way? i do not understand how it works..

Answer 6

Watch this video, and if you still need help, we'll jump in.

Answer 7

http://www.youtube.com/watch?v=aVVZOwo18k8&list=FLxFDZsq7_sDYcfK7w9lp-WA&index=3&feature=plpp_video

Answer 8

okay thank you

Answer 9

i look for the sin(x) because the given equation is sin(arctanx)?

Answer 10

From diagram, you need to find sin (theta). The guy above seem to be working it algebraically, but you can work it geometrically, just copy it from diagram