another expression for sin(tan^-1x)

Question

anonymous · Answer

let : tan y = x/1

sin y = x/ sqrt (x^2 + 1)

sin ( sin^-1 y) = y


sin ( sin^ -1  x/ sqrt (x^2 + 1))  = x/ sqrt (x^2 + 1)

anonymous · Answer

where is tan y= x/1 from??

anonymous · Answer

tan x  = 1

x = tan^-1 x

anonymous · Answer

sorry   x = tan^-1 1

anonymous · Answer

can you please explain it in easier way? i do not understand how it works..

anonymous · Answer

Watch this video, and if you still need help, we'll jump in.

anonymous · Answer

http://www.youtube.com/watch?v=aVVZOwo18k8&list=FLxFDZsq7_sDYcfK7w9lp-WA&index=3&feature=plpp_video

anonymous · Answer

okay thank you

anonymous · Answer

i look for the sin(x) because the given equation is sin(arctanx)?

anonymous · Answer

|dw:1353171887429:dw|From diagram, you need to find sin (theta). The guy above seem to be working it algebraically, but you can work it geometrically, just copy it from diagram