Question

.

Answer 1

hint:write 8 as 2^3

Answer 2

i assume its \(8^{-1/3}\)

Answer 3

\[(x)^{-} = \frac{1}{(x)^+}\]

Answer 4

I would actually make sure the exponent is positive by finding its reciprocal. That is: 1/(8^1/3)

Answer 5

\(\huge (a^m)^n=a^{mn}\)

Answer 6

after u put 8=2^3

Answer 7

confused ?

Answer 8

yup :)

Answer 9

welcome ^_^