Question

how do you find minimum and maximum values for example, of y=2x^2-8x+5 ?

Answer 1

in the quadratic equation \(\large y=f(x)=ax^2+bx+c \), the parabola will have a maximum if a<0, and have a minimum if a>0.

the maximum/minimum is obtained by plugging in the value \(\large p=-\frac{b}{2a} \) into the function. the vertex is (p, f(p))

Answer 2

would p be y or x

Answer 3

p is the x-value

Answer 4

ok so for this one is it x=2?

Answer 5

yes.... that's the x-coordinate of the vertex... is the vertex a max or min???

Answer 6

maximum

Answer 7

?

Answer 8

what is the "a" in your equation? is a<0 ???

Answer 9

a is 2 and it is not less than zero so its a minimum right ?

Answer 10

yes... :)

Answer 11

sorry got it confused

Answer 12

thanks!

Answer 13

yw...:)

Answer 14

wait... one more thing...

Answer 15

the question asks "how do you find the maximum/mininum".
i'm assuming they want the maximum/minimum so you'll need to find f(2).

Answer 16

could u explain this to me ?