Question

making sure
completely simplified expression of √ 128 is 4√ 8?

Answer 1

You can still simply it more here. 8 = 2 x 2 x 2, so 2 comes out as a pair.

Answer 2

my options are 2√ 32, 4√ 8, 8 √ 2, 11√ 2, 12√ 8 so is my answer incorrect?

Answer 3

sqrt128 = sqrt2 * sqrt 64 = 8 sqrt 2

Answer 4

how do u know which factor pair to choose?

Answer 5

that's what confuses me

Answer 6

look for known squares in this case 64

Answer 7

\[8\sqrt{2}\]It's that because you have 7 2's in the radical. You take 6 out as 3 pairs and those 3 2's multiplied are 2x2x2 = 8 and one stays under the radical.

Answer 8

ohh ok

Answer 9

I think I get it

Answer 10

It just takes time and practice.