helkp
Write the equation of a line in slope-intercept form that has a slope of -1/4 and passes through the point (8, -1)
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OpenStudy (anonymous):
@philo1234
OpenStudy (anonymous):
Slope intercept form is y=mx+b, where m= slope and b is the y-intercept
OpenStudy (anonymous):
\[y-(-1)=-\frac{ 1 }{ 4 }(x-8)\] point slope form now solve for y
OpenStudy (anonymous):
Use the point-slope form: y-y1=m(x-x1), where y1=-1 and x1=8, m=-1/4
OpenStudy (anonymous):
idk how to do tht?
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OpenStudy (anonymous):
just plug in the values that u got and then put y by itself on one side.
OpenStudy (anonymous):
i still dnt get it?
OpenStudy (anonymous):
y+1=-1/4(x-8), then solve for 'y'
OpenStudy (anonymous):
y+1=-1/4(x-8)
-1
OpenStudy (anonymous):
Solve for 'y' u know how to do that right?
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OpenStudy (anonymous):
no?
OpenStudy (anonymous):
@philo1234 ????
OpenStudy (anonymous):
I would suggest u get rid of the paretheses on the right hand side by multiplying each term in the paretheses by -1/4 . then subtract 1 from both sides
OpenStudy (anonymous):
y+1=-1/4
-1 -1
OpenStudy (anonymous):
now wat @philo1234
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OpenStudy (anonymous):
I know u r messing with me. I think u know what to do. But here it is anyways:
y+1 = -1/4x-8(-1/4)
y+1 = -1/4x+2
-1 -1
y = -1/4x+1