Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

Graph these inequalities!

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

I believe the answer to the first problem is -3≤x<2 and the 2nd is x>2 or x<-6

OpenStudy (anonymous):

@AriPotta help?!

OpenStudy (anonymous):

ok, i will try to help but write down the equation for me?

OpenStudy (anonymous):

I attached them above @MikiaseKebede

OpenStudy (anonymous):

\[\left| 2\chi+1\right|\le5\]

OpenStudy (anonymous):

ok i just want to get a clear shot at the problem

OpenStudy (anonymous):

OpenStudy (anonymous):

@MikiaseKebede

OpenStudy (anonymous):

ok, i see it

OpenStudy (anonymous):

ok first you want to solve the inequalities? right

OpenStudy (anonymous):

yeah I got -3≤x<2 and x>2 or x<-6

OpenStudy (anonymous):

@MikiaseKebede

jimthompson5910 (jim_thompson5910):

|2x+1| <= 5 -5 <= 2x+1 <= 5 -5-1 <= 2x <= 5-1 -6 <= 2x <= 4 -6/2 <= x <= 4/2 -3 <= x <= 2 So your first answer is correct but you forgot to say "or equal to" for the second inequality sign.

OpenStudy (anonymous):

oh whoopsy! but how do you graph those? like which answers are they? a,b,c, or d? @jim_thompson5910

jimthompson5910 (jim_thompson5910):

-3 <= x <= 2 means you'll have closed circles at -3 and 2. You'll then shade the region between -3 and 2

jimthompson5910 (jim_thompson5910):

this is basically a visual way of saying "x is between -3 and 2 (including both endpoints)"

OpenStudy (anonymous):

so the first one is B, correct? @jim_thompson5910

jimthompson5910 (jim_thompson5910):

correct

OpenStudy (anonymous):

and help on the 2nd one? @jim_thompson5910

jimthompson5910 (jim_thompson5910):

|2x+4| > 8 2x+4 > 8 or 2x+4 < -8 2x > 8-4 or 2x < -8-4 2x > 4 or 2x < -12 x > 4/2 or x < -12/2 x > 2 or x < -6 x < -6 or x > 2

OpenStudy (anonymous):

So that one is C? @jim_thompson5910

jimthompson5910 (jim_thompson5910):

exactly

OpenStudy (anonymous):

Thanks so much! @jim_thompson5910

jimthompson5910 (jim_thompson5910):

np

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!