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Mathematics 14 Online
OpenStudy (anonymous):

question attached inside!! :)

OpenStudy (anonymous):

part 1 of question :)

OpenStudy (anonymous):

part 2 (last part!) of the question :) they are connected, but just one problem :)

OpenStudy (anonymous):

A. -1 B. 27 C. 29 D. There isn't enough information to answer the question. idk :/

jimthompson5910 (jim_thompson5910):

all logs in this particular problem are base b

OpenStudy (anonymous):

kk so that means? haha :P

jimthompson5910 (jim_thompson5910):

log( (A^5C^2)/(D^6) ) = log(A^5C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = log(A^5) + log(C^2) - log(D^6) What's next?

jimthompson5910 (jim_thompson5910):

no i said that as a disclaimer to what I was about to write

OpenStudy (anonymous):

oh okay haha :P so do i simplify that more? or is that the most simplified it can get?

OpenStudy (anonymous):

or do i do substitution or sometihng?

jimthompson5910 (jim_thompson5910):

you can pull the exponents down

jimthompson5910 (jim_thompson5910):

using one of the rules given on that purplemath site

OpenStudy (anonymous):

oh no!! i lost the link :(

OpenStudy (anonymous):

can u pls resend it to me? :)

jimthompson5910 (jim_thompson5910):

http://www.purplemath.com/modules/logrules.htm

OpenStudy (anonymous):

okay so which one do i use?? I'm confused :(

jimthompson5910 (jim_thompson5910):

you use the rule that log(x^y) = y*log(x)

OpenStudy (anonymous):

so I'm trying to see what to put in here, but I'm stuck... idk :(

jimthompson5910 (jim_thompson5910):

log( (A^5C^2)/(D^6) ) = log(A^5C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = log(A^5) + log(C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = 5*log(A) + 2*log(C) - 6*log(D) Then do the proper substitutions

OpenStudy (anonymous):

ohhh i see what u did now! but how do i do proper substitutions??

jimthompson5910 (jim_thompson5910):

log(A) = 5, so replace log(A) with 5 do the same with the other logs

OpenStudy (anonymous):

so i get log(5)+log(2)-log(6) ??

jimthompson5910 (jim_thompson5910):

close

jimthompson5910 (jim_thompson5910):

you mixed up C and D though and you're missing your coefficients

OpenStudy (anonymous):

okay then, idk then :( iheartfood=a confused person atm :/

jimthompson5910 (jim_thompson5910):

look at the givens again

OpenStudy (anonymous):

the givens?

OpenStudy (anonymous):

what are the givens?? from the original question?

jimthompson5910 (jim_thompson5910):

yeah, log(A) = ..., log(C) = ..., etc

OpenStudy (anonymous):

okay so i get this? log(5)+log(7)-log(2) ??

jimthompson5910 (jim_thompson5910):

ok, now add on the coefficients

OpenStudy (anonymous):

what coefficients?? like the results when i enter it in the calc??

jimthompson5910 (jim_thompson5910):

oh wait, idk why i said that was right, I'm misreading lol

jimthompson5910 (jim_thompson5910):

log( (A^5C^2)/(D^6) ) = log(A^5C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = log(A^5) + log(C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = 5*log(A) + 2*log(C) - 6*log(D) log( (A^5C^2)/(D^6) ) = 5*5 + 2*7 - 6*2 log( (A^5C^2)/(D^6) ) = ???

jimthompson5910 (jim_thompson5910):

log(A) = 5 NOT log(5)

OpenStudy (anonymous):

wiat so what do i have now then?? I'm confused now lol

jimthompson5910 (jim_thompson5910):

no sry, but i put up the right way to do it

OpenStudy (anonymous):

so i have this so far?|dw:1353219981709:dw|??just making sure... idk if thats how I'm supposed to draw it?

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