Question

Let N = 999 999 999 999 999 999.
How many N's are there in N^2 ???

Answer 1

that be double the about of n
so 2 amounts of N

Answer 2

It's \(n^{2}\), not \(2n\), so wouldn't there be \(n\) \(n\)'s in \(n^{2}\)?

Answer 3

What does it mean by 'how many Ns'? There would be N of them...

Answer 4

Simpler example. If \(x\) = 9, how many \(x\)'s in \(x^{2}\)?

\(x^{2} = 81\), and there are 9 9's in 81.

Answer 5

there are N N's in N^2 :) question is not clear