Given A = 67o, B = 13o, and b = 20.3, which of the following can be used to solve the triangle? a. Law of Sines b. Law of Cosines c. Hero's Formula d. Cannot be solved.
those are degrees
cosine formula is a good option
Ah. Law of sines: \[\frac{\sin(a)}{A}=\frac{\sin(b)}{b}\] Law of cosines is \[c^2 = a^2+b^2 - 2ab\cos(C)\] So what are you given that can be used here?
cannot be solved
Sorry the law of sines should have been: \[\frac{\sin(A)}{a}=\frac{\sin(B)}{b}\]
the angles
oh and side b
Yes it can. You have 1 side and three angles
so law of sines?
And i flipped all my capitol letters with the convention. Yes, Multiple uses of Law of sines would solve the triangle. You would have to do a 180-a-b to get angle c though...
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